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How to Write the Net Ionic Equation for Ni (NO3)2 + Na3PO4 = Ni3 (PO4)2 + NaNO3

بواسطة Wayne Breslyn
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تم نشره في 2020/07/04

There are three main steps for writing the net ionic equation for Ni(NO3)2 + Na3PO4 = Ni3(PO4)2 + NaNO3 (Nickel (II) nitrate + Sodium phosphate). First, we balance the molecular equation. Second, we write the states and break the soluble ionic compounds into their ions (these are the strong electrolytes with an (aq) after them). Finally, we cross out any spectator ions. These are the ions that appear on both sides of the ionic equation. If you are unsure if a precipitate will be present when writing net ionic equations, you should consult a solubility table for the compound. Another option to determine if a precipitate forms is to have memorized the solubility rules. In this reaction, Ni3(PO4)2 will be insoluble and will be a precipitate (solid) and fall to the bottom of the test tube. We therefore write the state symbol (s) after the compound that precipitates out of solution. If you are unsure if a compound is soluble when writing net ionic equations you should consult a solubility table for the compound. How to balance the molecular equation for Ni(NO3)2 + Na3PO4: /watch/End2nFP9-0192 _________________ Important Skills Finding Ionic Charge for Elements: /watch/YEhHh1QY22MYH Memorizing Polyatomic Ions: /watch/kqZb_Mhxpevxb Determining Solubility: /watch/IJaV9K9EZv5EV More Practice Introduction to Net Ionic Equations: /watch/Y11NrI_HRXPHN Net Ionic Equations Practice: /watch/w95Ix2JasDhaI _________________ General Steps: 1. Write the balanced molecular equation. 2. Write the state (s, l, g, aq) for each substance. 3. Split soluble compounds into ions (the complete ionic equation). 4. Cross out the spectator ions on both sides of complete ionic equation. 5. Write the remaining substances as the net ionic equation. Writing and balancing net ionic equations is an important skill in chemistry and is essential for understanding solubility, electrochemistry, and focusing on the substances and ions involved in the chemical reaction and ignoring those that don’t (the spectator ions). More chemistry help at http://www.Breslyn.org

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